49x^2+14x+1-(7x+1)(3x-50)=0

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Solution for 49x^2+14x+1-(7x+1)(3x-50)=0 equation:


Simplifying
49x2 + 14x + 1 + -1(7x + 1)(3x + -50) = 0

Reorder the terms:
49x2 + 14x + 1 + -1(1 + 7x)(3x + -50) = 0

Reorder the terms:
49x2 + 14x + 1 + -1(1 + 7x)(-50 + 3x) = 0

Multiply (1 + 7x) * (-50 + 3x)
49x2 + 14x + 1 + -1(1(-50 + 3x) + 7x * (-50 + 3x)) = 0
49x2 + 14x + 1 + -1((-50 * 1 + 3x * 1) + 7x * (-50 + 3x)) = 0
49x2 + 14x + 1 + -1((-50 + 3x) + 7x * (-50 + 3x)) = 0
49x2 + 14x + 1 + -1(-50 + 3x + (-50 * 7x + 3x * 7x)) = 0
49x2 + 14x + 1 + -1(-50 + 3x + (-350x + 21x2)) = 0

Combine like terms: 3x + -350x = -347x
49x2 + 14x + 1 + -1(-50 + -347x + 21x2) = 0
49x2 + 14x + 1 + (-50 * -1 + -347x * -1 + 21x2 * -1) = 0
49x2 + 14x + 1 + (50 + 347x + -21x2) = 0

Reorder the terms:
1 + 50 + 14x + 347x + 49x2 + -21x2 = 0

Combine like terms: 1 + 50 = 51
51 + 14x + 347x + 49x2 + -21x2 = 0

Combine like terms: 14x + 347x = 361x
51 + 361x + 49x2 + -21x2 = 0

Combine like terms: 49x2 + -21x2 = 28x2
51 + 361x + 28x2 = 0

Solving
51 + 361x + 28x2 = 0

Solving for variable 'x'.

Factor a trinomial.
(51 + 4x)(1 + 7x) = 0

Subproblem 1

Set the factor '(51 + 4x)' equal to zero and attempt to solve: Simplifying 51 + 4x = 0 Solving 51 + 4x = 0 Move all terms containing x to the left, all other terms to the right. Add '-51' to each side of the equation. 51 + -51 + 4x = 0 + -51 Combine like terms: 51 + -51 = 0 0 + 4x = 0 + -51 4x = 0 + -51 Combine like terms: 0 + -51 = -51 4x = -51 Divide each side by '4'. x = -12.75 Simplifying x = -12.75

Subproblem 2

Set the factor '(1 + 7x)' equal to zero and attempt to solve: Simplifying 1 + 7x = 0 Solving 1 + 7x = 0 Move all terms containing x to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + 7x = 0 + -1 Combine like terms: 1 + -1 = 0 0 + 7x = 0 + -1 7x = 0 + -1 Combine like terms: 0 + -1 = -1 7x = -1 Divide each side by '7'. x = -0.1428571429 Simplifying x = -0.1428571429

Solution

x = {-12.75, -0.1428571429}

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